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Engineering Exams RRB-JE JE (Junior Engineer) CMA (Chemical and Metallurgical Assistant) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) Mathematics 2024 16.12.24 Paper-1 Shift-3 Medium +1 -0.33
Two pipes can fill a tank in 20 hours and 90 hours, respectively. The time (in hours) required to fill the tank when both pipes are opened simultaneously is:
Correct Answer: D. 180/11
Explanation: The correct answer is Option D: 180/11. To find the time taken when both pipes work together, we calculate their combined hourly rate. The first pipe fills 1/20 of the tank per hour, and the second pipe fills 1/90 of the tank per hour. Adding these rates gives (1/20 + 1/90), which simplifies to (9 + 2) / 180, or 11/180 of the tank per hour. To find the total time required to fill the entire tank, we take the reciprocal of this combined rate, resulting in 180/11 hours.
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