Based on the English alphabetical order, three of the following four letter-cluster pairs
are alike in a certain way and thus form a group. Which letter-cluster pair DOES NOT
belong to that group? (Note: The odd one out is not based on the number of
consonants/vowels or their position in the letter-cluster.)
-
A.
FI-NS
-
B.
VY-CI
-
C.
HK-OU
-
D.
SV-ZF
Correct Answer:
A. FI-NS
Explanation:
The correct answer is Option A: FI-NS.
To determine the pattern, calculate the numerical difference between the letters in each pair based on their positions in the alphabet: - Option B: VY-CI. V(22) to Y(25) is +3; C(3) to I(9) is +6.
- Option C: HK-OU. H(8) to K(11) is +3; O(15) to U(21) is +6.
- Option D: SV-ZF. S(19) to V(22) is +3; Z(26) to F(6) is +6.In options B, C, and D, the first set of letters has a gap of 3, while the second set has a gap of 6. However, in Option A (FI-NS), F(6) to I(9) is +3, but N(14) to S(19) is only +5. Therefore, FI-NS is the odd one out because it does not follow the +3, +6 pattern established by the others.
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