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Engineering Exams RRB-JE JE (Junior Engineer) CMA (Chemical and Metallurgical Assistant) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) Mathematics 2024 16.12.24 Paper-1 Shift-3 Hard +1 -0.33
A cylindrical rod has an outer curved surface area of 4500 cm2. If the length of the rod is 39 cm, then the outer radius (in cm) of the rod, correct to two places of decimal, is: (Take pi = 22/7)
Correct Answer: A. 18.36
Explanation: The correct answer is Option A: 18.36. To determine the outer radius of the cylindrical rod, you use the formula for the curved surface area of a cylinder, which is 2 * pi * radius * height. By substituting the given surface area of 4500 cm2 and the length of 39 cm into the equation, and using 22/7 for pi, the radius is calculated to be approximately 18.36 cm when rounded to two decimal places.
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