If x varies inversely as y³ - 1 and is equal to 7 when y = 2, find x when y = 6.
-
A.
49/215
-
B.
49/216
-
C.
50/216
-
D.
51/215
Correct Answer:
A. 49/215
Explanation:
The correct answer is Option A: 49/215.
The problem states that x varies inversely as (y^3 - 1), which can be expressed by the formula x = k / (y^3 - 1), where k is a constant. Using the given values where x = 7 and y = 2, we can solve for k: 7 = k / (2^3 - 1), which simplifies to 7 = k / 7, giving us k = 49. With the constant k identified, we can find the new value of x when y = 6 by substituting these values into the original equation: x = 49 / (6^3 - 1). This results in x = 49 / (216 - 1), which simplifies to 49/215.
Click below to open Discussion & Feedback
0 Issues
Please
login to comment or Report Issues.