The maximum height of a projectile is given by-
-
A.
(u sin á)/2g
-
B.
(u cos á)/2g
-
C.
(u sin2á)/g
-
D.
(u cos2á)/2g
Correct Answer:
A. (u sin á)/2g
Explanation:
The maximum height (H) of a projectile is the highest vertical point it reaches during its flight. At this peak, the vertical component of its velocity becomes zero. Using the kinematic equation v^2 = u^2 + 2as, where the final vertical velocity (v) is 0, the initial vertical velocity (u) is u sin(á), and acceleration (a) is -g, the formula is derived as H = (u^2 sin^2 á) / 2g. Therefore, the correct option is A.
Click below to open Discussion & Feedback
0 Issues
Please
login to comment or Report Issues.