The shape factor for a solid circular section of diameter D is equal to:
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A.
D/2 Pi
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B.
16/3 Pi
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C.
Pi D/8
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D.
15/2 Pi
Correct Answer:
B. 16/3 Pi
Explanation:
The shape factor for a solid circular section is the ratio of its plastic section modulus to its elastic section modulus. For a circle with diameter D, the plastic section modulus is (D^3)/6 and the elastic section modulus is (pi * D^3)/32. Dividing the plastic modulus by the elastic modulus results in 16/(3 * pi), which is approximately 1.7. This value represents the reserve strength of the beam after the onset of yielding.
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