A wire has a resistance of R. If its length is increased by a factor of 8 and its crosssectional
area is decreased by a factor of 4, what is its new resistance (R')?
-
A.
R' = 8 R
-
B.
R' = 16 R
-
C.
R' = 32 R
-
D.
R' = 2 R
Correct Answer:
C. R' = 32 R
Explanation:
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. When the length is increased by a factor of 8 and the area is decreased by a factor of 4, the resistance increases by 8 multiplied by 4, resulting in a new resistance that is 32 times the original value. Therefore, the new resistance R' is 32 R.
Click below to open Discussion & Feedback
0 Issues
Please
login to comment or Report Issues.