Radhika travels a distance of 230 km with speed of 46 km/h and 400 km with 100 km/h by her car. Find the average speed (in km/h) of Radhika.
Correct Answer:
A. 70
Explanation:
The relationship follows a pattern of subtracting 4 from the alphabetical position of each letter. For SKIB to OGNG: S(19)-4=O(15), K(11)-4=G(7), I(9)-4=E (Note: I to N is +5, let's re-evaluate).
Re-evaluating the pattern:
S(19) - 4 = O(15)
K(11) - 4 = G(7)
I(9) + 5 = N(14)
B(2) + 5 = G(7)
Pattern: -4, -4, +5, +5.
Applying this to CUCV:
C(3) - 4 = Y(25)
U(21) - 4 = Q(17)
C(3) + 5 = H(8)
V(22) + 5 = A(27/1)
This confirms the pattern is -4, -4, +5, +5.
Applying to QIRK:
Q(17) - 4 = M(13)
I(9) - 4 = E(5)
R(18) + 5 = W(23)
K(11) + 5 = P(16)
The resulting letters are MEWP.
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