What property of carbon allows it to form long chains and rings?
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A.
Ability to form covalent bonds
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B.
Ability to form stable bonds with other elements
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C.
Ability to form multiple bonds
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D.
Tendency to form single bonds
Correct Answer:
C. Ability to form multiple bonds
Explanation:
The logic follows a consistent subtraction of letters in the English alphabet. For SKIB to OGNG: S-4=O, K-4=G, I-5=D (wait, check logic again). Let's re-examine: S(19) to O(15) is -4, K(11) to G(7) is -4, I(9) to N(14) is +5, B(2) to G(7) is +5. Pattern: -4, -4, +5, +5. Testing CUCV to YQHA: C(3)-4=Y(25), U(21)-4=Q(17), C(3)+5=H(8), V(22)+5=A(1). Applying this to QIRK: Q(17)-4=M, I(9)-4=E, R(18)+5=W, K(11)+5=P. Therefore, QIRK relates to MEWP.
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