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Engineering Exams RRB-JE JE (Junior Engineer) CMA (Chemical and Metallurgical Assistant) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) Mathematics 2024 16.12.24 Paper-1 Shift-1 Easy +1 -0.33
The length of each of the two equal sides of an isosceles triangle is 100 cm each and the length of its base is 56 cm. The area (in cm2) of the triangle is:
Correct Answer: B. 2688
Explanation: The logic involves shifting each letter backward by 4 positions in the English alphabet. Applying this to SKIB: S - 4 = O K - 4 = G I - 4 = E (Note: The prompt indicates OGNG, suggesting a variation where the third letter might shift differently or there is a specific pattern, but testing the -4 shift on QIRK matches the options). Applying the -4 shift to QIRK: Q - 4 = M I - 4 = E R - 4 = N (Based on standard patterns, however, comparing M E \_ \_ to the options) K - 4 = G Looking at the options provided (MWEP, MWPE, MEPW, MEWP): The relationship in SKIB to OGNG and CUCV to YQHA follows a pattern where: 1st letter: -4 (S to O) 2nd letter: -4 (K to G) 3rd letter: -4 (I to E) 4th letter: -2 (B to Z/G is -2 in a different cycle, or specific offset) Following the consistent -4, -4, -4, -4 logic for QIRK: Q (-4) = M I (-4) = E R (-4) = N K (-4) = G However, evaluating the provided options against QIRK: Q to M (-4) I to E (-4) R to W (+5) K to P (+5) This does not fit perfectly. Re-evaluating the pattern from SKIB to OGNG: S(19) to O(15) = -4 K(11) to G(7) = -4 I(9) to N(14) = +5 B(2) to G(7) = +5 Applying -4, -4, +5, +5 to QIRK: Q(17) - 4 = M(13) -\> M I(9) - 4 = E(5) -\> E R(18) + 5 = W(23) -\> W K(11) + 5 = P(16) -\> P Result: MEWP
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