Which of the following pairs is INCORRECT?
-
A.
BCl3- SP2 hybridisation
-
B.
H2O - SP hybridisation
-
C.
BeCl2 - SP hybridisation
-
D.
CH4 - SP3 hybridisation
Correct Answer:
B. H2O - SP hybridisation
Explanation:
The hybridization of a molecule is determined by the number of sigma bonds and lone pairs on the central atom. In H2O, the oxygen atom has two sigma bonds with hydrogen atoms and two lone pairs of electrons. This results in a steric number of four, which corresponds to SP3 hybridization, not SP hybridization. The other pairs are correct: BCl3 is SP2 hybridized due to three sigma bonds and no lone pairs; BeCl2 is SP hybridized with two sigma bonds and no lone pairs; and CH4 is SP3 hybridized with four sigma bonds and no lone pairs. Thus, the pair H2O - SP hybridization is incorrect.
Click below to open Discussion & Feedback
0 Issues
Please
login to comment or Report Issues.