A Gaussian spherical surface of radius R enclosing a charge Q, has an outward flux ϕ associated with it. What will be the new outward flux associated with the Gaussian spherical surface, if the radius of the Gaussian surface is doubled?
Correct Answer:
D. ϕ
Explanation:
According to Gauss's Law, the net electric flux (ϕ) passing through any closed surface is determined solely by the total charge enclosed within that surface, divided by the permittivity of free space. Mathematically, this is expressed as ϕ = Q/ε₀. This relationship shows that the outward flux is independent of the shape or size of the Gaussian surface. Therefore, if the radius of the spherical surface is doubled while the enclosed charge (Q) remains the same, the total electric flux passing through the surface will not change. The new outward flux remains ϕ.
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