A student mixed lead(II) nitrate solution with potassium iodide solution. What was observed?
-
A.
Evolution of hydrogen gas
-
B.
No visible change
-
C.
Formation of a yellow precipitate
-
D.
Change in colour to green
Correct Answer:
C. Formation of a yellow precipitate
Explanation:
When lead(II) nitrate solution reacts with potassium iodide solution, a double displacement reaction occurs, resulting in the formation of lead(II) iodide and potassium nitrate. The lead(II) iodide produced is an insoluble solid that appears as a distinct yellow precipitate. This chemical change is represented by the equation: Pb(NO3)2 + 2KI → PbI2 + 2KNO3. Therefore, the observation of a yellow precipitate confirms that the reaction has taken place.
Click below to open Discussion & Feedback
0 Issues
Please
login to comment or Report Issues.