Consider that a nucleus with A = 240 is breaking into two fragments each of A = 120. What will be the total gain in binding energy, if binding energy per nucleon (Ebn) for A = 240 nucleus is about 7.6 MeV and for the two A = 120 fragment nuclei is about 8.5 MeV?
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A.
216 MeV
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B.
204 MeV
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C.
182.4 MeV
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D.
240 MeV
Correct Answer:
A. 216 MeV
Explanation:
To find the total energy gain, we compare the binding energies of the initial and final states. The initial binding energy for a nucleus with A = 240 is 1824 MeV (240 × 7.6 MeV/nucleon). When it splits into two A = 120 fragments, the total binding energy increases to 2040 MeV (240 × 8.5 MeV/nucleon). Therefore, the energy gained in the process is 2040 MeV - 1824 MeV = 216 MeV.
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