What will be the energy gained by an electron with charge q = 1.6×10–19 C, when accelerated through a potential difference (ΔV) = 1 volt?
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A.
1.6 × 1019 J
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B.
1.6 × 10–19J
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C.
10–19J
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D.
1019J
Correct Answer:
B. 1.6 × 10–19J
Explanation:
The energy acquired by a charge moving through a potential difference is determined by the formula E = q?V. Given an electron charge (q) of 1.6 × 10–19 C and a potential difference (?V) of 1 volt, the calculation is (1.6 × 10–19 C) × (1 V), which equals 1.6 × 10–19 Joules. This amount of energy is also defined as one electron-volt (eV), representing the kinetic energy gained by a single electron as it accelerates through a one-volt electric potential.
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