A paper weight is kept on a tabletop. The mass of paper weight is 0.5 kg and its dimensions are 10 cm × 4 cm × 2 cm. Find the pressure exerted by the paper weight on the table top if it is made to lie on the table top with its sides of dimensions 10 cm × 2 cm. (Take g = 9.8 m/s2)
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A.
612.5 Nm−2
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B.
2420 Nm−2
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C.
2450 Nm−2
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D.
49 Nm−2
Correct Answer:
C. 2450 Nm−2
Explanation:
To find the pressure exerted by the paper weight, first calculate the force (weight) using the formula F = m × g. With a mass of 0.5 kg and gravity at 9.8 m/s², the force is 4.9 N. Next, determine the contact area by multiplying the dimensions of the side touching the table: 10 cm (0.1 m) × 2 cm (0.02 m) equals 0.002 m². Pressure is calculated by dividing the force by the area (P = F / A), which results in 4.9 N / 0.002 m², giving a final pressure of 2450 Nm?².
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