A simply supported beam of 10 m carries a uniformly distributed load (UDL) of 5 kN/m over its entire span. What is the reaction force at each support?
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A.
20 kN
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B.
30 kN
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C.
25 kN
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D.
50 kN
Correct Answer:
C. 25 kN
Explanation:
To determine the support reactions for a 10m simply supported beam with a 5kN/m UDL, first find the total force: 5 kN/m * 10 m = 50 kN. Because the load is symmetric, it is distributed equally between the two supports. Thus, the reaction force at each end is 50 kN / 2 = 25 kN. This matches option C.
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