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Engineering Exams RRB-JE CS (Chemical Supervisor - Research) Technical Abilities 2025 22.04.25 Paper-2 Shift-2 Easy +1 -0.33
For a certain material, the values of transmissivity and reflectivity are specified as 0.88 and 0.07, respectively. The absorptivity of that material is .
Correct Answer: C. 0.05
Explanation: In thermodynamics, the sum of a material's transmissivity, reflectivity, and absorptivity must equal one (1 = α + ρ + τ). Given a transmissivity of 0.88 and a reflectivity of 0.07, the absorptivity is calculated by subtracting these values from the total (1 - 0.88 - 0.07), which results in 0.05.
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