Which of the following are the Miller Indices of a close packed plane in the FCC crystal?
-
A.
-100
-
B.
-112
-
C.
-110
-
D.
-111
Correct Answer:
D. -111
Explanation:
In a Face-Centered Cubic (FCC) crystal, the close-packed planes are the {111} family. These planes have the highest atomic packing density because they consist of atoms arranged in a triangular, nestled pattern that maximizes space efficiency. In a unit cell, these planes intersect the x, y, and z axes at equal distances (or their negatives), resulting in Miller indices such as (111), (-111), (1-11), and (11-1). Because the atoms are most tightly packed along these specific crystallographic orientations, they are the primary planes for slip and deformation in FCC materials. Therefore, among the given choices, -111 represents a member of this close-packed family.
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