Select the correct statement valid only for reversible process conducted by closed system; neglect change in kinetic and potential energy.
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A.
TdS = dU + TdV
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B.
TdS = dU + WdS
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C.
dQ = dU + TdS
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D.
dQ = dU + pdV
Correct Answer:
D. dQ = dU + pdV
Explanation:
For a closed system undergoing a reversible process where changes in kinetic and potential energy are negligible, the correct statement is dQ = dU + pdV. This is derived from the first law of thermodynamics, which states that the heat added to a system (dQ) equals the change in its internal energy (dU) plus the work done by the system. In a reversible process, the work done is specifically defined as the product of pressure and the change in volume (pdV). While TdS = dU + pdV is also a valid thermodynamic identity, it applies to any process between equilibrium states, whereas dQ = TdS is only strictly true for reversible processes.
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