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Engineering Exams RRB-JE JE (Junior Engineer) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) Mathematics 2019 24-May-2019 Paper-1 Shift-2 Medium +1 -0.33 CMA (Chemical and Metallurgical Assistant)
Rs.26000 is split into two sums such that the Simple Interest on one part for 5 years at 10% equals the Simple Interest on the other part for 6 years at 9%. What is the sum placed at 10% for 5 years?
Correct Answer: D. Rs.13500
Explanation: To find the sum placed at 10%, let the two parts of the Rs. 26,000 be x and (26,000 - x). According to the simple interest formula (Principal × Rate × Time / 100), the interest for the first part is (x × 10 × 5) / 100, and for the second part, it is ((26,000 - x) × 9 × 6) / 100. Setting these interests equal gives 50x = 54(26,000 - x). Simplifying this equation leads to 50x = 1,404,000 - 54x, which further simplifies to 104x = 1,404,000. Dividing 1,404,000 by 104 results in x = 13,500. Thus, the amount invested at 10% for 5 years is Rs. 13,500.
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