Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. What is the time taken by the slower train to cross the faster train in seconds?
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A.
48 seconds
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B.
45 seconds
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C.
36 seconds
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D.
49 seconds
Correct Answer:
A. 48 seconds
Explanation:
To find the time taken for the two trains to cross each other, first calculate the relative speed. Since they are moving in opposite directions, their speeds are added together: 60 km/hr + 90 km/hr = 150 km/hr. To convert this to meters per second, multiply by 5/18, resulting in approximately 41.67 m/s (or 125/3 m/s). Next, determine the total distance to be covered, which is the sum of the lengths of both trains: 1.10 km + 0.9 km = 2.0 km, or 2000 meters. Finally, calculate the time by dividing the total distance by the relative speed: 2000 / (125/3) = 48 seconds. Therefore, it takes 48 seconds for the slower train to cross the faster one.
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