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Engineering Exams RRB-JE JE (Junior Engineer) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) General Science 2019 24-May-2019 Paper-1 Shift-2 Easy +1 -0.33 CMA (Chemical and Metallurgical Assistant)
A concave lens has a focal length 15 cm. If the object is placed at 30 cm from the lens, what is the image distance?
Correct Answer: B. -10 cm
Explanation: To calculate the image distance for a concave lens, we use the lens formula: 1/f = 1/v - 1/u.1. Identify the given values using the sign convention: - The focal length (f) for a concave lens is always negative, so f = -15 cm. - The object distance (u) is measured against the direction of incident light, making it negative, so u = -30 cm.2. Plug the values into the lens formula: 1/(-15) = 1/v - 1/(-30) 3. Simplify the equation: \-1/15 = 1/v + 1/30 4. Isolate 1/v: 1/v = -1/15 - 1/30 5. Find a common denominator (30) to solve: 1/v = -2/30 - 1/30 1/v = -3/30 1/v = -1/10 6. Solve for v: v = -10 cmThe negative sign indicates that the image is virtual and formed on the same side of the lens as the object. Therefore, the image distance is -10 cm.
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