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Engineering Exams RRB-JE JE (Junior Engineer) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) Mathematics 2019 24-May-2019 Paper-1 Shift-2 Easy +1 -0.33 CMA (Chemical and Metallurgical Assistant)
Average age of 3 children born at intervals of 2 years is 8. How old is the eldest child?
Correct Answer: D. 10 years
Explanation: To find the age of the oldest child, we first determine the total age of all three children by multiplying the average age of 8 by 3, which equals 24. Let the age of the youngest child be represented by x. Since the children were born at two-year intervals, their ages can be expressed as x, x + 2, and x + 4. By adding these together (x + x + 2 + x + 4 = 24), we find that 3x + 6 = 24. Subtracting 6 from both sides gives 3x = 18, and dividing by 3 reveals the youngest child is 6 years old. To find the eldest child's age, we add 4 to the youngest child's age (6 + 4), resulting in 10 years.
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