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Engineering Exams RRB-JE JE (Junior Engineer) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) Mathematics 2019 24-May-2019 Paper-1 Shift-2 Easy +1 -0.33 CMA (Chemical and Metallurgical Assistant)
What is the maturity value of Rs.25000 at the end of 2 years at 9.25% Simple Interest?
Correct Answer: A. Rs.29625
Explanation: To calculate the maturity value, first determine the simple interest earned. Using the formula for simple interest (Principal × Rate × Time / 100), multiply the principal of Rs. 25,000 by the annual interest rate of 9.25% and the duration of 2 years. This calculation (25,000 × 0.0925 × 2) results in an interest amount of Rs. 4,625. Finally, add this interest to the original principal (25,000 + 4,625) to find the total maturity value, which is Rs. 29,625.
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