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Engineering Exams RRB-JE JE (Junior Engineer) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) Mathematics 2019 24-May-2019 Paper-1 Shift-2 Medium +1 -0.33 CMA (Chemical and Metallurgical Assistant)
Find the greatest number that will divide 115, 149 and 183 leaving remainders 3, 5, 7 respectively.
Correct Answer: D. 16
Explanation: To find the greatest number that divides 115, 149, and 183 with remainders of 3, 5, and 7 respectively, first subtract the remainders from the numbers: 115 - 3 = 112, 149 - 5 = 144, and 183 - 7 = 176. The required number is the Highest Common Factor (HCF) of 112, 144, and 176. Calculating the HCF: 112 = 16 x 7, 144 = 16 x 9, and 176 = 16 x 11. Since 16 is the largest common divisor for all three values, the correct answer is 16.
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