A boat moving upstream takes 8 hours 48 minutes to cover a distance while it takes 4 hours to return to the starting point, downstream. What is the ratio of the speed of boat in still water to that of water current?
-
A.
3:2
-
B.
4:3
-
C.
8:3
-
D.
2:1
Correct Answer:
C. 8:3
Explanation:
To find the ratio of the boat's speed in still water to the speed of the current, we first convert the upstream travel time of 8 hours and 48 minutes into a single unit, which equals 8.8 hours. Let the speed of the boat in still water be represented by B and the speed of the water current by C. The speed while moving upstream is the difference between the two (B - C), and the speed while moving downstream is their sum (B + C). Since the distance covered in both directions is identical, we can set up the equation: 8.8(B - C) = 4(B + C). Simplifying this expression gives 8.8B - 8.8C = 4B + 4C, which further reduces to 4.8B = 12.8C. Dividing both sides leads to the ratio B/C = 12.8 / 4.8, which simplifies to 8/3. Thus, the ratio of the boat's speed to the current's speed is 8:3.
Click below to open Discussion & Feedback
0 Issues
Please
login to comment or Report Issues.