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Engineering Exams RRB-JE JE (Junior Engineer) CMA (Chemical and Metallurgical Assistant) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) General Intelligence and Reasoning 2019 24.05.2019 Paper-1 Shift-1 Easy +1 -0.33
Find the ODD one out from the given options.
Correct Answer: D. E
Explanation: To solve the problem, first express the given equation algebraically. If 20% of a = b, then 0.2a = b. Next, determine the value of b% of 20 by substituting the expression for b: (b / 100) \* 20 = (0.2a / 100) \* 20 Simplifying the calculation: (0.2a \* 20) / 100 = 4a / 100 = 4% of a Therefore, b% of 20 is equivalent to 4% of a.
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