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Engineering Exams RRB-JE JE (Junior Engineer) CMA (Chemical and Metallurgical Assistant) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) Mathematics 2019 24.05.2019 Paper-1 Shift-1 +1 -0.33 Medium
John cycles at 10 km/h to reach his destination at 2 PM. If he travels at 15 km/h, he will reach at 12 noon itself. At what speed should he travel to reach the place at 1 PM?
Correct Answer: A. 12 km/h
Explanation: To find the required speed to reach the destination at 1 PM, we first determine the total distance using the relationship between speed, time, and distance (Distance = Speed × Time).1. Determine the Time Difference: The difference between arriving at 2 PM and 12 noon is 2 hours. If the time taken at 10 km/h is t hours, the time taken at 15 km/h is t - 2 hours. 2. Calculate the Distance: Since the distance (D) is the same in both scenarios, we set up the equation: - 10t = 15(t - 2) - 10t = 15t - 30 - 5t = 30 - t = 6 hours Using t = 6, the distance is D = 10 km/h × 6 hours = 60 km.3. Calculate the Target Speed: To reach the destination at 1 PM (which is 1 hour earlier than 2 PM), the journey must take 5 hours (6 - 1 = 5). - Speed = Distance / Time - Speed = 60 km / 5 hours = 12 km/h.John must travel at 12 km/h to reach his destination at 1 PM.
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