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Engineering Exams RRB-JE JE (Junior Engineer) CMA (Chemical and Metallurgical Assistant) DMS (Depot Material Superintendent) CS (Chemical Supervisor - Research) MS (Metallurgical Supervisor - Research) Mathematics 2019 24.05.2019 Paper-1 Shift-1 +1 -0.33 Medium
Find the greatest number of 4 digits divisible by 15, 25, 40 and 75.
Correct Answer: A. 9600
Explanation: To solve this, first establish the relationship between a and b. Since 20% of a equals b, this can be written as 0.20a = b or a = 5b. The question asks for the value of b% of 20, which is calculated as (b/100) * 20, simplifying to b/5. By substituting b = 0.20a into this expression, we get (0.20a)/5, which equals 0.04a. Therefore, b% of 20 is equivalent to 4% of a.
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